Difficulty : Medium
Related Topics : HashTable
Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
- Each row must contain the digits
1-9
without repetition.- Each column must contain the digits
1-9
without repetition.- Each of the 9
3x3
sub-boxes of the grid must contain the digits1-9
without repetition.A partially filled sudoku which is valid.
The Sudoku board could be partially filled, where empty cells are filled with the character
'.'
.Input: [ ["5","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] Output: true
Input: [ ["8","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] Output: false Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
- A Sudoku board (partially filled) could be valid but is not necessarily solvable.
- Only the filled cells need to be validated according to the mentioned rules.
- The given board contain only digits
1-9
and the character'.'
.- The given board size is always
9x9
.
- mine
- Java
Runtime: 2 ms, faster than 87.53%, Memory Usage: 42.9 MB, less than 26.65% of Java online submissions
// O(R*C)time // O(R)space public boolean isValidSudoku(char[][] board) { int[] r = new int[10]; int[] c = new int[10]; int[] nine = new int[10]; for(int i = 0; i < board.length; i++){ for(int j = 0; j < board[i].length; j++){ if(board[i][j] == '.')continue; int v = board[i][j] - '0'; int t = 1 << v; int index = i / 3 * 3 + j / 3; if((r[i] & t) != 0 || (c[j] & t) != 0 || (nine[index] & t) != 0){ return false; } r[i] += t; c[j] += t; nine[index] += t; } } return true; }
- Java