Given a 2D integer matrix M representing the gray scale of an image, you need to design a smoother to make the gray scale of each cell becomes the average gray scale (rounding down) of all the 8 surrounding cells and itself. If a cell has less than 8 surrounding cells, then use as many as you can.
Input: [[1,1,1], [1,0,1], [1,1,1]] Output: [[0, 0, 0], [0, 0, 0], [0, 0, 0]] Explanation: For the point (0,0), (0,2), (2,0), (2,2): floor(3/4) = floor(0.75) = 0 For the point (0,1), (1,0), (1,2), (2,1): floor(5/6) = floor(0.83333333) = 0 For the point (1,1): floor(8/9) = floor(0.88888889) = 0
- The value in the given matrix is in the range of [0, 255].
- The length and width of the given matrix are in the range of [1, 150].
- mine
i can't got what it mean.
- the most votes
Your runtime beats 16.44 % of java submissions.
public class ImageSmoother {
public int[][] imageSmoother(int[][] M) {
if (M == null) return null;
int rows = M.length;
if (rows == 0) return new int[0][];
int cols = M[0].length;
int result[][] = new int[rows][cols];
for (int row = 0; row < rows; row++) {
for (int col = 0; col < cols; col++) {
int count = 0;
int sum = 0;
for (int incR : new int[]{-1, 0, 1}) {
for (int incC : new int[]{-1, 0, 1}) {
if (isValid(row + incR, col + incC, rows, cols)) {
count++;
sum += M[row + incR][col + incC];
}
}
}
result[row][col] = sum / count;
}
}
return result;
}
private boolean isValid(int x, int y, int rows, int cols) {
return x >= 0 && x < rows && y >= 0 && y < cols;
}
}
- Solution
Your runtime beats 66.18 % of java submissions.
O(N)time O(N)space, where N is the number of pixels in our image.
class Solution {
public int[][] imageSmoother(int[][] M) {
int R = M.length, C = M[0].length;
int[][] ans = new int[R][C];
for (int r = 0; r < R; ++r)
for (int c = 0; c < C; ++c) {
int count = 0;
for (int nr = r-1; nr <= r+1; ++nr){
for (int nc = c-1; nc <= c+1; ++nc) {
if (0 <= nr && nr < R && 0 <= nc && nc < C) {
ans[r][c] += M[nr][nc];
count++;
}
}
}
ans[r][c] /= count;
}
return ans;
}
}